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(x(x+1)/2)=15
We move all terms to the left:
(x(x+1)/2)-(15)=0
We multiply all the terms by the denominator
(x(x+1)-15*2)=0
We calculate terms in parentheses: +(x(x+1)-15*2), so:We get rid of parentheses
x(x+1)-15*2
We add all the numbers together, and all the variables
x(x+1)-30
We multiply parentheses
x^2+x-30
Back to the equation:
+(x^2+x-30)
x^2+x-30=0
a = 1; b = 1; c = -30;
Δ = b2-4ac
Δ = 12-4·1·(-30)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*1}=\frac{10}{2} =5 $
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