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(x(x-1))/x-5=x(x-9
We move all terms to the left:
(x(x-1))/x-5-(x(x-9)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
(x(x-1))-((x(x-9)-5)*x=0
We calculate terms in parentheses: +(x(x-1)), so:We get rid of parentheses
x(x-1)
We multiply parentheses
x^2-1x
Back to the equation:
+(x^2-1x)
x^2-1x-((x(x-9)-5)*x=0
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