(x)(1)+(3)(.50)=(3+x)(.80)

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Solution for (x)(1)+(3)(.50)=(3+x)(.80) equation: 



(x)(1)+(3)(.50)=(3+x)(.80)

We move all terms to the left:

(x)(1)+(3)(.50)-((3+x)(.80))=0

We add all the numbers together, and all the variables

x1-((x+3)(0.8))+3(0.5)=0

We add all the numbers together, and all the variables

x-((x+3)(0.8))+1.5=0

We multiply parentheses ..

x-((+0.8x+2.4))+1.5=0



We calculate terms in parentheses: -((+0.8x+2.4)), so:

(+0.8x+2.4)

We add all the numbers together, and all the variables

(0.8x+2.4)

We get rid of parentheses

0.8x+2.4

Back to the equation:

-(0.8x+2.4)



We get rid of parentheses

x-0.8x-2.4+1.5=0

We add all the numbers together, and all the variables

0.2x-0.9=0

We move all terms containing x to the left, all other terms to the right

0.2x=0.9

x=0.9/0.2

x=4+0.1/0.2

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