(x)(2x+1)(x-2)(2x-3)=63

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Solution for (x)(2x+1)(x-2)(2x-3)=63 equation: 



(x)(2x+1)(x-2)(2x-3)=63

We move all terms to the left:

(x)(2x+1)(x-2)(2x-3)-(63)=0

We multiply parentheses ..

x(+2x^2-4x+x-2)(2x-3)-63=0

We move all terms containing x to the left, all other terms to the right

x(+2x^2-4x+x-2)(2x-3)=63

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