(x)(2x+8)=192

Solution for (x)(2x+8)=192 equation:

(x)(2x+8)=192

We move all terms to the left:

(x)(2x+8)-(192)=0

We multiply parentheses

2x^2+8x-192=0

a = 2; b = 8; c = -192;
Δ = b2-4ac
Δ = 82-4·2·(-192)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-40}{2*2}=\frac{-48}{4}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+40}{2*2}=\frac{32}{4}
=8
$