(x)(2x-3)=196

Solution for (x)(2x-3)=196 equation:

(x)(2x-3)=196

We move all terms to the left:

(x)(2x-3)-(196)=0

We multiply parentheses

2x^2-3x-196=0

a = 2; b = -3; c = -196;
Δ = b2-4ac
Δ = -32-4·2·(-196)
Δ = 1577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1577}}{2*2}=\frac{3-\sqrt{1577}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1577}}{2*2}=\frac{3+\sqrt{1577}}{4}
$