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(x)(3x-8)=1675
We move all terms to the left:
(x)(3x-8)-(1675)=0
We multiply parentheses
3x^2-8x-1675=0
a = 3; b = -8; c = -1675;
Δ = b2-4ac
Δ = -82-4·3·(-1675)
Δ = 20164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20164}=142$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-142}{2*3}=\frac{-134}{6} =-22+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+142}{2*3}=\frac{150}{6} =25 $
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