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(x)(5x-3)=36
We move all terms to the left:
(x)(5x-3)-(36)=0
We multiply parentheses
5x^2-3x-36=0
a = 5; b = -3; c = -36;
Δ = b2-4ac
Δ = -32-4·5·(-36)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*5}=\frac{-24}{10} =-2+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*5}=\frac{30}{10} =3 $
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