(x)(x)-(x-4)(x-4)=128

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Solution for (x)(x)-(x-4)(x-4)=128 equation:


Simplifying
(x)(x) + -1(x + -4)(x + -4) = 128

Multiply x * x
x2 + -1(x + -4)(x + -4) = 128

Reorder the terms:
x2 + -1(-4 + x)(x + -4) = 128

Reorder the terms:
x2 + -1(-4 + x)(-4 + x) = 128

Multiply (-4 + x) * (-4 + x)
x2 + -1(-4(-4 + x) + x(-4 + x)) = 128
x2 + -1((-4 * -4 + x * -4) + x(-4 + x)) = 128
x2 + -1((16 + -4x) + x(-4 + x)) = 128
x2 + -1(16 + -4x + (-4 * x + x * x)) = 128
x2 + -1(16 + -4x + (-4x + x2)) = 128

Combine like terms: -4x + -4x = -8x
x2 + -1(16 + -8x + x2) = 128
x2 + (16 * -1 + -8x * -1 + x2 * -1) = 128
x2 + (-16 + 8x + -1x2) = 128

Reorder the terms:
-16 + 8x + x2 + -1x2 = 128

Combine like terms: x2 + -1x2 = 0
-16 + 8x + 0 = 128
-16 + 8x = 128

Solving
-16 + 8x = 128

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 8x = 128 + 16

Combine like terms: -16 + 16 = 0
0 + 8x = 128 + 16
8x = 128 + 16

Combine like terms: 128 + 16 = 144
8x = 144

Divide each side by '8'.
x = 18

Simplifying
x = 18

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