(x)(x)-2(X)(X)=x(2-2x)-4

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Solution for (x)(x)-2(X)(X)=x(2-2x)-4 equation: 



(x)(x)-2(x)(x)=x(2-2x)-4

We move all terms to the left:

(x)(x)-2(x)(x)-(x(2-2x)-4)=0

We add all the numbers together, and all the variables

xx-2xx-(x(-2x+2)-4)=0



We calculate terms in parentheses: -(x(-2x+2)-4), so:

x(-2x+2)-4

We multiply parentheses

-2x^2+2x-4

Back to the equation:

-(-2x^2+2x-4)



We get rid of parentheses

2x^2-2x+xx-2xx+4=0

We move all terms containing x to the left, all other terms to the right

2x^2-2x+xx-2xx=-4

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