(x)(x)-8x+32=0

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Solution for (x)(x)-8x+32=0 equation:


Simplifying
(x)(x) + -8x + 32 = 0

Multiply x * x
x2 + -8x + 32 = 0

Reorder the terms:
32 + -8x + x2 = 0

Solving
32 + -8x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-32' to each side of the equation.
32 + -8x + -32 + x2 = 0 + -32

Reorder the terms:
32 + -32 + -8x + x2 = 0 + -32

Combine like terms: 32 + -32 = 0
0 + -8x + x2 = 0 + -32
-8x + x2 = 0 + -32

Combine like terms: 0 + -32 = -32
-8x + x2 = -32

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -32 + 16

Reorder the terms:
16 + -8x + x2 = -32 + 16

Combine like terms: -32 + 16 = -16
16 + -8x + x2 = -16

Factor a perfect square on the left side:
(x + -4)(x + -4) = -16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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