(x)(x+1)=(x)(x+1)+1

Solution for (x)(x+1)=(x)(x+1)+1 equation:

Simplifying
(x)(x + 1) = (x)(x + 1) + 1

Reorder the terms:
x(1 + x) = (x)(x + 1) + 1
(1 * x + x * x) = (x)(x + 1) + 1
(1x + x2) = (x)(x + 1) + 1

Reorder the terms:
1x + x2 = x(1 + x) + 1
1x + x2 = (1 * x + x * x) + 1
1x + x2 = (1x + x2) + 1

Reorder the terms:
1x + x2 = 1 + 1x + x2

Add '-1x' to each side of the equation.
1x + -1x + x2 = 1 + 1x + -1x + x2

Combine like terms: 1x + -1x = 0
0 + x2 = 1 + 1x + -1x + x2
x2 = 1 + 1x + -1x + x2

Combine like terms: 1x + -1x = 0
x2 = 1 + 0 + x2
x2 = 1 + x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 1 + 0
0 = 1

Solving
0 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.