(x)(x+1)=3306

Solution for (x)(x+1)=3306 equation:

(x)(x+1)=3306

We move all terms to the left:

(x)(x+1)-(3306)=0

We multiply parentheses

x^2+x-3306=0

a = 1; b = 1; c = -3306;
Δ = b2-4ac
Δ = 12-4·1·(-3306)
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13225}=115$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-115}{2*1}=\frac{-116}{2}
=-58
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+115}{2*1}=\frac{114}{2}
=57
$