If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x)(x+16)=384
We move all terms to the left:
(x)(x+16)-(384)=0
We multiply parentheses
x^2+16x-384=0
a = 1; b = 16; c = -384;
Δ = b2-4ac
Δ = 162-4·1·(-384)
Δ = 1792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1792}=\sqrt{256*7}=\sqrt{256}*\sqrt{7}=16\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16\sqrt{7}}{2*1}=\frac{-16-16\sqrt{7}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16\sqrt{7}}{2*1}=\frac{-16+16\sqrt{7}}{2} $
| 12(x+3)=5(2x+5)=2x | | 12(x+3)=5(2x+5)+2x | | 5b+6b=33 | | 0.6x-5=7+0.1x | | --51=-3+6x | | (x+2)(x+3)(x+4)=24 | | (D3+D2+4D+4)y=0. | | 7x–10=5x+10 | | 20=x+22 | | 2x=6=-14 | | -25=x+22 | | 8z-17=-15 | | 10=x/3=90 | | z-13=-57 | | b-62=-55 | | n-28=-49 | | a-60=-52 | | q-54=-46 | | m-46=-38 | | 5+(5t+1)=25t-7 | | X²-4x=-4 | | 4(x-7)+1=3x | | 3x*5=75 | | 8n-5=7(8n-5)+5 | | 4x-9=-8x+5 | | 5(4x-3)=10(2x-8) | | 5(x+1)-6x=11x | | -24y=168 | | 5m-4=2m-9 | | ⅔x+5=13 | | 8(y+2)/8=48/8 | | 2(h-4)+4h=3(2h-9)+1 |