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(x)(x+2)=1680
We move all terms to the left:
(x)(x+2)-(1680)=0
We multiply parentheses
x^2+2x-1680=0
a = 1; b = 2; c = -1680;
Δ = b2-4ac
Δ = 22-4·1·(-1680)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-82}{2*1}=\frac{-84}{2} =-42 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+82}{2*1}=\frac{80}{2} =40 $
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