(x)(x+4)=(4(x+2))-40

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Solution for (x)(x+4)=(4(x+2))-40 equation:


Simplifying
(x)(x + 4) = (4(x + 2)) + -40

Reorder the terms:
x(4 + x) = (4(x + 2)) + -40
(4 * x + x * x) = (4(x + 2)) + -40
(4x + x2) = (4(x + 2)) + -40

Reorder the terms:
4x + x2 = (4(2 + x)) + -40
4x + x2 = ((2 * 4 + x * 4)) + -40
4x + x2 = ((8 + 4x)) + -40
4x + x2 = (8 + 4x) + -40

Remove parenthesis around (8 + 4x)
4x + x2 = 8 + 4x + -40

Reorder the terms:
4x + x2 = 8 + -40 + 4x

Combine like terms: 8 + -40 = -32
4x + x2 = -32 + 4x

Add '-4x' to each side of the equation.
4x + -4x + x2 = -32 + 4x + -4x

Combine like terms: 4x + -4x = 0
0 + x2 = -32 + 4x + -4x
x2 = -32 + 4x + -4x

Combine like terms: 4x + -4x = 0
x2 = -32 + 0
x2 = -32

Solving
x2 = -32

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Simplifying
x2 = -32

Reorder the terms:
32 + x2 = -32 + 32

Combine like terms: -32 + 32 = 0
32 + x2 = 0

The solution to this equation could not be determined.

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