(x)+(x+2)+(x+4)=56

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Solution for (x)+(x+2)+(x+4)=56 equation: 



(x)+(x+2)+(x+4)=56

We move all terms to the left:

(x)+(x+2)+(x+4)-(56)=0

We get rid of parentheses

x+x+x+2+4-56=0

We add all the numbers together, and all the variables

3x-50=0

We move all terms containing x to the left, all other terms to the right

3x=50

x=50/3

x=16+2/3

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