(x)+(x+1)+(x+2)=48

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Solution for (x)+(x+1)+(x+2)=48 equation: 



(x)+(x+1)+(x+2)=48

We move all terms to the left:

(x)+(x+1)+(x+2)-(48)=0

We get rid of parentheses

x+x+x+1+2-48=0

We add all the numbers together, and all the variables

3x-45=0

We move all terms containing x to the left, all other terms to the right

3x=45

x=45/3

x=15

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