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(x)+(x+1)=3(x+2)
We move all terms to the left:
(x)+(x+1)-(3(x+2))=0
We get rid of parentheses
x+x-(3(x+2))+1=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
2x-(3x+6)+1=0
We get rid of parentheses
2x-3x-6+1=0
We add all the numbers together, and all the variables
-1x-5=0
We move all terms containing x to the left, all other terms to the right
-x=5
x=5/-1
x=-5
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