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(x)-(8/3)(x)=-10
We move all terms to the left:
(x)-(8/3)(x)-(-10)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+8/3)x-(-10)=0
We add all the numbers together, and all the variables
x-(+8/3)x+10=0
We multiply parentheses
-8x^2+x+10=0
a = -8; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-8)·10
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{321}}{2*-8}=\frac{-1-\sqrt{321}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{321}}{2*-8}=\frac{-1+\sqrt{321}}{-16} $
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