(x)/(x+2)+(x)/(x-2)=1

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Solution for (x)/(x+2)+(x)/(x-2)=1 equation: 


D( x )

x-2 = 0

x+2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

x/(x+2)+x/(x-2) = 1 // - 1

x/(x+2)+x/(x-2)-1 = 0

(x*(x-2))/((x+2)*(x-2))+(x*(x+2))/((x+2)*(x-2))+(-1*(x+2)*(x-2))/((x+2)*(x-2)) = 0

x*(x-2)+x*(x+2)-1*(x+2)*(x-2) = 0

2*x^2-x^2+4 = 0

x^2+4 = 0

(x^2+4)/((x+2)*(x-2)) = 0

(x^2+4)/((x+2)*(x-2)) = 0 // * (x+2)*(x-2)

x^2+4 = 0

1*x^2 = -4 // : 1

x^2 = -4

x belongs to the empty set

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