(x)/5=5+(x-4)/(2)

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Solution for (x)/5=5+(x-4)/(2) equation: 



(x)/5=5+(x-4)/(2)

We move all terms to the left:

(x)/5-(5+(x-4)/(2))=0

We calculate fractions


2x^2/()+(-(5+(x-4)*5)/()=0



We calculate terms in parentheses: +(-(5+(x-4)*5)/(), so:

-(5+(x-4)*5)/(

We multiply all the terms by the denominator


-(5+(x-4)*5)



We calculate terms in parentheses: -(5+(x-4)*5), so:

5+(x-4)*5

determiningTheFunctionDomain
(x-4)*5+5

We multiply parentheses

5x-20+5

We add all the numbers together, and all the variables

5x-15

Back to the equation:

-(5x-15)



We get rid of parentheses

-5x+15

Back to the equation:

+(-5x+15)



We get rid of parentheses

2x^2/()-5x+15=0

We multiply all the terms by the denominator


2x^2-5x*()+15*()=0

We add all the numbers together, and all the variables

2x^2-5x*()=0

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