(x)=(x)(x)+16x-22

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Solution for (x)=(x)(x)+16x-22 equation: 



(x)=(x)(x)+16x-22

We move all terms to the left:

(x)-((x)(x)+16x-22)=0

We add all the numbers together, and all the variables

x-(16x+xx-22)=0

We get rid of parentheses

x-16x-xx+22=0

We add all the numbers together, and all the variables

-15x-xx+22=0

We move all terms containing x to the left, all other terms to the right

-15x-xx=-22

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