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(x)=(x+3)+(3x-5)
We move all terms to the left:
(x)-((x+3)+(3x-5))=0
We calculate terms in parentheses: -((x+3)+(3x-5)), so:We get rid of parentheses
(x+3)+(3x-5)
We get rid of parentheses
x+3x+3-5
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
x-4x+2=0
We add all the numbers together, and all the variables
-3x+2=0
We move all terms containing x to the left, all other terms to the right
-3x=-2
x=-2/-3
x=2/3
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