(x)=(x+3)+(3x-5)

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Solution for (x)=(x+3)+(3x-5) equation: 



(x)=(x+3)+(3x-5)

We move all terms to the left:

(x)-((x+3)+(3x-5))=0



We calculate terms in parentheses: -((x+3)+(3x-5)), so:

(x+3)+(3x-5)

We get rid of parentheses

x+3x+3-5

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

x-4x+2=0

We add all the numbers together, and all the variables

-3x+2=0

We move all terms containing x to the left, all other terms to the right

-3x=-2

x=-2/-3

x=2/3

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