(x)=15-x2+4x

Solution for (x)=15-x2+4x equation:

(x)=15-x2+4x

We move all terms to the left:

(x)-(15-x2+4x)=0

We add all the numbers together, and all the variables

-(-1x^2+4x+15)+x=0

We get rid of parentheses

1x^2-4x+x-15=0

We add all the numbers together, and all the variables

x^2-3x-15=0

a = 1; b = -3; c = -15;
Δ = b2-4ac
Δ = -32-4·1·(-15)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{69}}{2*1}=\frac{3-\sqrt{69}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{69}}{2*1}=\frac{3+\sqrt{69}}{2}
$