(x)=150x2+585x+525(x)=15x+21

Solution for (x)=150x2+585x+525(x)=15x+21 equation:

(x)=150x^2+585x+525(x)=15x+21

We move all terms to the left:

(x)-(150x^2+585x+525(x))=0

We get rid of parentheses

-150x^2+x-585x-525x=0

We add all the numbers together, and all the variables

-150x^2-1109x=0

a = -150; b = -1109; c = 0;
Δ = b2-4ac
Δ = -11092-4·(-150)·0
Δ = 1229881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1229881}=1109$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1109)-1109}{2*-150}=\frac{0}{-300}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1109)+1109}{2*-150}=\frac{2218}{-300}
=-7+59/150
$