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(x)=8/3x-16
We move all terms to the left:
(x)-(8/3x-16)=0
Domain of the equation: 3x-16)!=0We get rid of parentheses
x∈R
x-8/3x+16=0
We multiply all the terms by the denominator
x*3x+16*3x-8=0
Wy multiply elements
3x^2+48x-8=0
a = 3; b = 48; c = -8;
Δ = b2-4ac
Δ = 482-4·3·(-8)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-20\sqrt{6}}{2*3}=\frac{-48-20\sqrt{6}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+20\sqrt{6}}{2*3}=\frac{-48+20\sqrt{6}}{6} $
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