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(x)=9x^2+162x+6
We move all terms to the left:
(x)-(9x^2+162x+6)=0
We get rid of parentheses
-9x^2+x-162x-6=0
We add all the numbers together, and all the variables
-9x^2-161x-6=0
a = -9; b = -161; c = -6;
Δ = b2-4ac
Δ = -1612-4·(-9)·(-6)
Δ = 25705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-161)-\sqrt{25705}}{2*-9}=\frac{161-\sqrt{25705}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-161)+\sqrt{25705}}{2*-9}=\frac{161+\sqrt{25705}}{-18} $
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