(x)=9x2-18x

Solution for (x)=9x2-18x equation:

(x)=9x^2-18x

We move all terms to the left:

(x)-(9x^2-18x)=0

We get rid of parentheses

-9x^2+x+18x=0

We add all the numbers together, and all the variables

-9x^2+19x=0

a = -9; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-9)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-9}=\frac{-38}{-18}
=2+1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-9}=\frac{0}{-18}
=0
$