(x)=x(2x+3600)

Solution for (x)=x(2x+3600) equation:

(x)=x(2x+3600)

We move all terms to the left:

(x)-(x(2x+3600))=0


We calculate terms in parentheses: -(x(2x+3600)), so:

x(2x+3600)

We multiply parentheses

2x^2+3600x

Back to the equation:

-(2x^2+3600x)


We get rid of parentheses

-2x^2+x-3600x=0

We add all the numbers together, and all the variables

-2x^2-3599x=0

a = -2; b = -3599; c = 0;
Δ = b2-4ac
Δ = -35992-4·(-2)·0
Δ = 12952801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12952801}=3599$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3599)-3599}{2*-2}=\frac{0}{-4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3599)+3599}{2*-2}=\frac{7198}{-4}
=-1799+1/2
$