(x*2+2x-5)=(-2x-4x+7)

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Solution for (x*2+2x-5)=(-2x-4x+7) equation: 



(x*2+2x-5)=(-2x-4x+7)

We move all terms to the left:

(x*2+2x-5)-((-2x-4x+7))=0

We add all the numbers together, and all the variables

(2x+x*2-5)-((-6x+7))=0

We get rid of parentheses

2x+x*2-((-6x+7))-5=0



We calculate terms in parentheses: -((-6x+7)), so:

(-6x+7)

We get rid of parentheses

-6x+7

Back to the equation:

-(-6x+7)



Wy multiply elements

2x+2x-(-6x+7)-5=0

We get rid of parentheses

2x+2x+6x-7-5=0

We add all the numbers together, and all the variables

10x-12=0

We move all terms containing x to the left, all other terms to the right

10x=12

x=12/10

x=1+1/5

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