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(x*3)(x*5)=9
We move all terms to the left:
(x*3)(x*5)-(9)=0
We add all the numbers together, and all the variables
(+x*3)(+x*5)-9=0
We multiply parentheses ..
(+15x^2)-9=0
We get rid of parentheses
15x^2-9=0
a = 15; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·15·(-9)
Δ = 540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{540}=\sqrt{36*15}=\sqrt{36}*\sqrt{15}=6\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{15}}{2*15}=\frac{0-6\sqrt{15}}{30} =-\frac{6\sqrt{15}}{30} =-\frac{\sqrt{15}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{15}}{2*15}=\frac{0+6\sqrt{15}}{30} =\frac{6\sqrt{15}}{30} =\frac{\sqrt{15}}{5} $
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