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(x*x)+10x=95.97
We move all terms to the left:
(x*x)+10x-(95.97)=0
We add all the numbers together, and all the variables
(+x*x)+10x-(95.97)=0
We add all the numbers together, and all the variables
10x+(+x*x)-95.97=0
We get rid of parentheses
10x+x*x-95.97=0
Wy multiply elements
x^2+10x-95.97=0
a = 1; b = 10; c = -95.97;
Δ = b2-4ac
Δ = 102-4·1·(-95.97)
Δ = 483.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{483.88}}{2*1}=\frac{-10-\sqrt{483.88}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{483.88}}{2*1}=\frac{-10+\sqrt{483.88}}{2} $
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