(x*x)+2=(x-2)(x+4)

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Solution for (x*x)+2=(x-2)(x+4) equation: 



(x*x)+2=(x-2)(x+4)

We move all terms to the left:

(x*x)+2-((x-2)(x+4))=0

We add all the numbers together, and all the variables

(+x*x)-((x-2)(x+4))+2=0

We get rid of parentheses

x*x-((x-2)(x+4))+2=0

We multiply parentheses ..

-((+x^2+4x-2x-8))+x*x+2=0



We calculate terms in parentheses: -((+x^2+4x-2x-8)), so:

(+x^2+4x-2x-8)

We get rid of parentheses

x^2+4x-2x-8

We add all the numbers together, and all the variables

x^2+2x-8

Back to the equation:

-(x^2+2x-8)



Wy multiply elements

x^2-(x^2+2x-8)+2=0

We get rid of parentheses

x^2-x^2-2x+8+2=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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