(x*x)+64=(x*x)+(x*)+49

Solution for (x*x)+64=(x*x)+(x*)+49 equation:

(x*x)+64=(x*x)+(x*)+49

We move all terms to the left:

(x*x)+64-((x*x)+(x*)+49)=0

We add all the numbers together, and all the variables

(+x*x)-((+x*x)+(+x*)+49)+64=0

We get rid of parentheses

x*x-((+x*x)+(+x*)+49)+64=0


We calculate terms in parentheses: -((+x*x)+(+x*)+49), so:

(+x*x)+(+x*)+49

We get rid of parentheses

x*x+x*+49

Wy multiply elements

x^2+x*+49

Back to the equation:

-(x^2+x*+49)


Wy multiply elements

x^2-(x^2+x*+49)+64=0

We get rid of parentheses

x^2-x^2-x*-49+64=0

We add all the numbers together, and all the variables

-x*+15=0

We move all terms containing x to the left, all other terms to the right

-x*=-15

x=-15/1

x=-15