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(x*x)+x=50
We move all terms to the left:
(x*x)+x-(50)=0
We add all the numbers together, and all the variables
(+x*x)+x-50=0
We add all the numbers together, and all the variables
x+(+x*x)-50=0
We get rid of parentheses
x+x*x-50=0
Wy multiply elements
x^2+x-50=0
a = 1; b = 1; c = -50;
Δ = b2-4ac
Δ = 12-4·1·(-50)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{201}}{2*1}=\frac{-1-\sqrt{201}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{201}}{2*1}=\frac{-1+\sqrt{201}}{2} $
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