(x*x)-25/3x*24/2x-10

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Solution for (x*x)-25/3x*24/2x-10 equation:


x in (-oo:+oo)

x*x-(((24*(25/3)*x)/2)*x)-10 = 0

x*x-100*x^2-10 = 0

-99*x^2 = 10 // : -99

x^2 = -10/99

x belongs to the empty set

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