If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x*x)-3x=100
We move all terms to the left:
(x*x)-3x-(100)=0
We add all the numbers together, and all the variables
(+x*x)-3x-100=0
We add all the numbers together, and all the variables
-3x+(+x*x)-100=0
We get rid of parentheses
-3x+x*x-100=0
Wy multiply elements
x^2-3x-100=0
a = 1; b = -3; c = -100;
Δ = b2-4ac
Δ = -32-4·1·(-100)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{409}}{2*1}=\frac{3-\sqrt{409}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{409}}{2*1}=\frac{3+\sqrt{409}}{2} $
| (4n-1)=(3n-7) | | -7t+14=-7 | | 1.1x+2.36=-8.1 | | 4=r+91-3 | | c+(-6)=11 | | 10(p+3)=70 | | 7b−7=6b | | m/5-2=2 | | (8^x)^3x=24 | | -16=-9+s | | 23−3k=5 | | 5(j-94)=30 | | 5(j−94)=30 | | 1=f/2-9 | | 9(x^2)-6x+37=0 | | f/5+65=72 | | -13+4c=39 | | 35=5(p-79) | | 35=5(p−79) | | (9x^2)-6x+37=0 | | 100=5(2x+4)-5 | | -23+7n=-5(8n-9) | | -8x+22=15x-2-14x | | 8y-18=3y+9 | | g-48-6=-8 | | -4x-5=-4-5x | | g−48-6=-8 | | 5x×8=42 | | 5(r-67)=100 | | -9(x+6)=-207. | | 5(r−67)=100 | | 6(q+11)=90 |