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(x+(x+1))*3=70-((x+2)+(x+3))
We move all terms to the left:
(x+(x+1))*3-(70-((x+2)+(x+3)))=0
We calculate terms in parentheses: -(70-((x+2)+(x+3))), so:We get rid of parentheses
70-((x+2)+(x+3))
determiningTheFunctionDomain -((x+2)+(x+3))+70
We calculate terms in parentheses: -((x+2)+(x+3)), so:We get rid of parentheses
(x+2)+(x+3)
We get rid of parentheses
x+x+2+3
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
-2x-5+70
We add all the numbers together, and all the variables
-2x+65
Back to the equation:
-(-2x+65)
(x+(x+1))*3+2x-65=0
We add all the numbers together, and all the variables
2x+(x+(x+1))*3-65=0
We move all terms containing x to the left, all other terms to the right
2x+(x+(x+1))*3=65
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