(x+(x+1)+(x+2)+(x+3)+(x+4))/4=60

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Solution for (x+(x+1)+(x+2)+(x+3)+(x+4))/4=60 equation: 



(x+(x+1)+(x+2)+(x+3)+(x+4))/4=60

We move all terms to the left:

(x+(x+1)+(x+2)+(x+3)+(x+4))/4-(60)=0

We multiply all the terms by the denominator


(x+(x+1)+(x+2)+(x+3)+(x+4))-60*4=0



We calculate terms in parentheses: +(x+(x+1)+(x+2)+(x+3)+(x+4)), so:

x+(x+1)+(x+2)+(x+3)+(x+4)

We get rid of parentheses

x+x+x+x+x+1+2+3+4

We add all the numbers together, and all the variables

5x+10

Back to the equation:

+(5x+10)



We add all the numbers together, and all the variables

(5x+10)-240=0

We get rid of parentheses

5x+10-240=0

We add all the numbers together, and all the variables

5x-230=0

We move all terms containing x to the left, all other terms to the right

5x=230

x=230/5

x=46

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