(x+(x+2)+(x+4)+(x+6))/4=27

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Solution for (x+(x+2)+(x+4)+(x+6))/4=27 equation:



(x+(x+2)+(x+4)+(x+6))/4=27
We move all terms to the left:
(x+(x+2)+(x+4)+(x+6))/4-(27)=0
We multiply all the terms by the denominator
(x+(x+2)+(x+4)+(x+6))-27*4=0
We calculate terms in parentheses: +(x+(x+2)+(x+4)+(x+6)), so:
x+(x+2)+(x+4)+(x+6)
We get rid of parentheses
x+x+x+x+2+4+6
We add all the numbers together, and all the variables
4x+12
Back to the equation:
+(4x+12)
We add all the numbers together, and all the variables
(4x+12)-108=0
We get rid of parentheses
4x+12-108=0
We add all the numbers together, and all the variables
4x-96=0
We move all terms containing x to the left, all other terms to the right
4x=96
x=96/4
x=24

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