(x+(x+2)+(x+4)+(x+6))/4=27

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Solution for (x+(x+2)+(x+4)+(x+6))/4=27 equation: 



(x+(x+2)+(x+4)+(x+6))/4=27

We move all terms to the left:

(x+(x+2)+(x+4)+(x+6))/4-(27)=0

We multiply all the terms by the denominator


(x+(x+2)+(x+4)+(x+6))-27*4=0



We calculate terms in parentheses: +(x+(x+2)+(x+4)+(x+6)), so:

x+(x+2)+(x+4)+(x+6)

We get rid of parentheses

x+x+x+x+2+4+6

We add all the numbers together, and all the variables

4x+12

Back to the equation:

+(4x+12)



We add all the numbers together, and all the variables

(4x+12)-108=0

We get rid of parentheses

4x+12-108=0

We add all the numbers together, and all the variables

4x-96=0

We move all terms containing x to the left, all other terms to the right

4x=96

x=96/4

x=24

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