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(x+(x-1))/4=3x+1
We move all terms to the left:
(x+(x-1))/4-(3x+1)=0
We get rid of parentheses
(x+(x-1))/4-3x-1=0
We multiply all the terms by the denominator
(x+(x-1))-3x*4-1*4=0
We calculate terms in parentheses: +(x+(x-1)), so:We add all the numbers together, and all the variables
x+(x-1)
We get rid of parentheses
x+x-1
We add all the numbers together, and all the variables
2x-1
Back to the equation:
+(2x-1)
(2x-1)-3x*4-4=0
Wy multiply elements
(2x-1)-12x-4=0
We get rid of parentheses
2x-12x-1-4=0
We add all the numbers together, and all the variables
-10x-5=0
We move all terms containing x to the left, all other terms to the right
-10x=5
x=5/-10
x=-1/2
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