(x+)(x-)=x2+3x+28

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Solution for (x+)(x-)=x2+3x+28 equation: 



(x+)(x-)=x2+3x+28

We move all terms to the left:

(x+)(x-)-(x2+3x+28)=0

We add all the numbers together, and all the variables

-(+x^2+3x+28)+(+x)(+x)=0

We get rid of parentheses

-x^2-3x+(+x)(+x)-28=0

We multiply parentheses ..

-x^2+(+x^2)-3x-28=0

We add all the numbers together, and all the variables

-1x^2+(+x^2)-3x-28=0

We get rid of parentheses

-1x^2+x^2-3x-28=0

We add all the numbers together, and all the variables

-3x-28=0

We move all terms containing x to the left, all other terms to the right

-3x=28

x=28/-3

x=-9+1/3

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