(x+)(x-)=x2+4x-96

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Solution for (x+)(x-)=x2+4x-96 equation: 



(x+)(x-)=x2+4x-96

We move all terms to the left:

(x+)(x-)-(x2+4x-96)=0

We add all the numbers together, and all the variables

-(+x^2+4x-96)+(+x)(+x)=0

We get rid of parentheses

-x^2-4x+(+x)(+x)+96=0

We multiply parentheses ..

-x^2+(+x^2)-4x+96=0

We add all the numbers together, and all the variables

-1x^2+(+x^2)-4x+96=0

We get rid of parentheses

-1x^2+x^2-4x+96=0

We add all the numbers together, and all the variables

-4x+96=0

We move all terms containing x to the left, all other terms to the right

-4x=-96

x=-96/-4

x=+24

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