(x+)4+(4x)+(10x-10)=288

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Solution for (x+)4+(4x)+(10x-10)=288 equation: 



(x+)4+(4x)+(10x-10)=288

We move all terms to the left:

(x+)4+(4x)+(10x-10)-(288)=0

We add all the numbers together, and all the variables

(+x)4+4x+(10x-10)-288=0

We add all the numbers together, and all the variables

4x+(+x)4+(10x-10)-288=0

We multiply parentheses

4x+4x+(10x-10)-288=0

We get rid of parentheses

4x+4x+10x-10-288=0

We add all the numbers together, and all the variables

18x-298=0

We move all terms containing x to the left, all other terms to the right

18x=298

x=298/18

x=16+5/9

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