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(x+-5)(40+-1x)=124
We move all terms to the left:
(x+-5)(40+-1x)-(124)=0
We add all the numbers together, and all the variables
(x-5)(-1x)-124=0
We multiply parentheses ..
(-1x^2+5x)-124=0
We get rid of parentheses
-1x^2+5x-124=0
a = -1; b = 5; c = -124;
Δ = b2-4ac
Δ = 52-4·(-1)·(-124)
Δ = -471
Delta is less than zero, so there is no solution for the equation
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