(x+0.5)(x+0.5)=0.64

Solution for (x+0.5)(x+0.5)=0.64 equation:

(x+0.5)(x+0.5)=0.64

We move all terms to the left:

(x+0.5)(x+0.5)-(0.64)=0

We add all the numbers together, and all the variables

(x+0.5)(x+0.5)-0.64=0

We multiply parentheses ..

(+x^2+0.5x+0.5x+0.25)-0.64=0

We get rid of parentheses

x^2+0.5x+0.5x+0.25-0.64=0

We add all the numbers together, and all the variables

x^2+x-0.39=0

a = 1; b = 1; c = -0.39;
Δ = b2-4ac
Δ = 12-4·1·(-0.39)
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2.56}}{2*1}=\frac{-1-\sqrt{2.56}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2.56}}{2*1}=\frac{-1+\sqrt{2.56}}{2}
$