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(x+0.6)(x+1.4)=0
We multiply parentheses ..
(+x^2+1.4x+0.6x+0.84)=0
We get rid of parentheses
x^2+1.4x+0.6x+0.84=0
We add all the numbers together, and all the variables
x^2+2x+0.84=0
a = 1; b = 2; c = +0.84;
Δ = b2-4ac
Δ = 22-4·1·0.84
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{0.64}}{2*1}=\frac{-2-\sqrt{0.64}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{0.64}}{2*1}=\frac{-2+\sqrt{0.64}}{2} $
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