(x+1)(-3-3x)=0

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Solution for (x+1)(-3-3x)=0 equation: 



(x+1)(-3-3x)=0

We add all the numbers together, and all the variables

(x+1)(-3x-3)=0

We multiply parentheses ..

(-3x^2-3x-3x-3)=0

We get rid of parentheses

-3x^2-3x-3x-3=0

We add all the numbers together, and all the variables

-3x^2-6x-3=0

a = -3; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·(-3)·(-3)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{-6}=-1$

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