(x+1)(2x+1)=(x+3)(2x+3)

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Solution for (x+1)(2x+1)=(x+3)(2x+3) equation: 



(x+1)(2x+1)=(x+3)(2x+3)

We move all terms to the left:

(x+1)(2x+1)-((x+3)(2x+3))=0

We multiply parentheses ..

(+2x^2+x+2x+1)-((x+3)(2x+3))=0



We calculate terms in parentheses: -((x+3)(2x+3)), so:

(x+3)(2x+3)

We multiply parentheses ..

(+2x^2+3x+6x+9)

We get rid of parentheses

2x^2+3x+6x+9

We add all the numbers together, and all the variables

2x^2+9x+9

Back to the equation:

-(2x^2+9x+9)



We get rid of parentheses

2x^2-2x^2+x+2x-9x+1-9=0

We add all the numbers together, and all the variables

-6x-8=0

We move all terms containing x to the left, all other terms to the right

-6x=8

x=8/-6

x=-1+1/3

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